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When object is thrown upward it rises to height "h" how high is the object in terms of h, when it has lost one third of its original Kinetic Energy?
  1. h/4
  2. h/3
  3. h/2
  4. None of these
Explanation
  • The total mechanical energy (kinetic + potential) remains constant.
  • Initially, the object has total energy E = K + U = mgh.
  • When it loses 1/3 of its kinetic energy, the remaining kinetic energy is 2/3 of the initial value.
  • Using energy conservation, solving for height gives h/2.

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